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Math 161 Final Exam Version 1 (144 points)
Precalculus I
2022 May 09
John Scalea
Page 1
2 answers: 4 points; #1 and #2: 8 points total each; 20 points
146 points
1. Consider y = 2 | (5/2)x â€“ 10 | â€“ 4
2. Consider 4x â€“ 6y = -3
y = 2 | (5/2)(x â€“ 4) | â€“ 4
6y = 4x â€“ 3 so y = (2/3)x â€“ (1/2)
For each equation, complete the table below. Then sketch a graph of the equation on the axes below.
domain
range
x-intercept(s)
y-intercept
slope
vertex
as x â†’ -âˆž, f(x) â†’
as x â†’ âˆž, f(x) â†’
0 = 2 | (5/2)x â€“ 10 | â€“ 4
4 = 2 | (5/2)x â€“ 10 |
2 = | (5/2)x â€“ 10 |
all real numbers
y â‰¥ -4
(16/5, 0), (24/5, 0)
(0, 16)
xxxxxxx
(4, -4)
âˆž
âˆž
all real numbers
all real numbers
(-3/4, 0)
(0, 1/2)
2/3
xxxxxxx
-âˆž
âˆž
(5/2)x â€“ 10 = 2 or (5/2)x â€“ 10 = -2
(5/2)x = 12 or (5/2)x = 8
x = 24/5 or x = 16/5
3. Solve -2(4 â€“ 5x) + 3x = -1 + (3 â€“ 2x) for x. Present your answer as a simplified fraction.
____________ x = 2/3 (self)
-8 + 10x + 3x = -1 + 3 â€“ 2x
-8 + 13x = 2 â€“ 2x
15x = 10
x = 10/15 = 2/3